Use Gaussian elimination to find the complete solution to the system of equations, or state that none exists.
x + y + z = 9
2x - 3y + 4z = 7
x - 4y + 3z = -2
A. {(-7z/5+34/5 ,2z/5 +11/5 , z)}
b. {(- 7z/5+34/5 , 2z/5- 11/5 , z)}
c . {( z/5+ 34/5 , 2z/5+11/5 , z)}
C?
oh ho, now Gauss Jordan. We are cooking with gas here
But there is a limit to what I am going to try to type
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
Okay but my answer is C is that wrong or right ?
strange answer choices, arbitrary z
hang on
I don't know how to use that calculator , I've tried
Okay tHANKS
0 , 29/7 , 34/7 it says
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
Hmm okay thanks anyways , I'ma just move on and check my other one
put in
+1 +1 +1 +9
+3 -3 +4 +7
+1 -4 +3 -2
3 rows, 4 columns
Those answer choices are wrong
whoops, 2 not three in row 2 beginning
put in
+1 +1 +1 +9
+2 -3 +4 +7
+1 -4 +3 -2
Thanks you
34/5 11/5 undefined 0
can not solve for z, bottom row all zero
put arbitrary z in and see what happens
34/5 + 11/5 + z = 9 ?
z = 9 - 9 = 0
2 * 34/5 - 3 * 11/5 + 4z = 7
7 + 4 z = 7
z = 0
ah ha, B
-7 z/5 + 2 z/5 + z IS ZERO LOL
Talk about fooling the student !