Math

1)How many real number solutions does the equation have? -8x^2-8x-2=0
A) One Solution
B) Two Solutions
C) No solutions
D) Infinitely many solutions

If someone could help me with this that would be great since I am confused. Thank you!

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asked by Tia
  1. One solution. if your talking about discriminant

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    posted by Rose
  2. Sorry! its no real solution. because when you do discriminant i get a negative number so it would be no real solution

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    posted by Rose
  3. -8x^2-8x-2=0
    or
    4x^2 + 4x + 1 = 0
    discrm = 16 - 4(4)(1) = 0
    thus there is one solution.

    check:
    4x^2 + 4x + 1 = 0
    (2x + 1)^2 = 0
    2x+1 = 0
    x = -1/2

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    posted by Reiny

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