Math
1)How many real number solutions does the equation have? 8x^28x2=0
A) One Solution
B) Two Solutions
C) No solutions
D) Infinitely many solutions
If someone could help me with this that would be great since I am confused. Thank you!
asked by
Tia

One solution. if your talking about discriminant
posted by Rose

Sorry! its no real solution. because when you do discriminant i get a negative number so it would be no real solution
posted by Rose

8x^28x2=0
or
4x^2 + 4x + 1 = 0
discrm = 16  4(4)(1) = 0
thus there is one solution.
check:
4x^2 + 4x + 1 = 0
(2x + 1)^2 = 0
2x+1 = 0
x = 1/2posted by Reiny
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