For any two vectors u and v show that
(u.v)^2-[(u.v)×v].u = u^2v^2
your operations make no sense
u.v is a scalar, so (u.v)xv is undefined
naturally, vxv=0, so u.vxv = 0
if u is a vector, what does u^2 mean?
(u.v)^2-[(u.v)×v].u = u^2v^2
u.v is a scalar, so (u.v)xv is undefined
naturally, vxv=0, so u.vxv = 0
if u is a vector, what does u^2 mean?