draw two figures such that the first one has a greater perimeter but smallaer area than the second
For example :
First :
Rectangle 18 x 2
Perimeter = 2 * 18 + 2 * 2 = 36 + 4 = 40
Area = 18 * 2 = 36
Second :
Rectangle 7 x 6
Perimeter = 2 * 7 + 2 * 6 = 14 + 12 = 26
Area = 7 * 6 = 42
To draw two figures where the first one has a greater perimeter but a smaller area than the second, we can start by considering different shapes and their properties. Let's use rectangles as an example.
1. Figure 1: A long and narrow rectangle
- Draw a rectangle with a length L and a width W, where L > W.
- Calculate the perimeter of the rectangle by using the formula: P = 2(L + W).
- In this case, since the length is relatively longer than the width, the perimeter will be greater.
- Calculate the area of the rectangle using the formula: A = L * W.
- As the length is greater than the width, the area will be smaller compared to Figure 2.
2. Figure 2: A square or a shorter rectangle
- Draw a square or a rectangle with a length L' and a width W', where L' ≤ W'.
- Calculate the perimeter of the rectangle using the formula: P' = 2(L' + W').
- In this case, since the length is relatively shorter than the width or equal in the case of a square, the perimeter will be smaller.
- Calculate the area of the rectangle using the formula: A' = L' * W'.
- As the length is shorter than or equal to the width, the area will be greater compared to Figure 1.
By following these instructions, you can draw two figures where the first one has a greater perimeter but a smaller area than the second. Feel free to adjust the dimensions and shapes to explore different possibilities.