chemistry

I'm having trouble balancing this equation in a basic solution.

Cr(OH)3 + Br2 -----> CrO4{2-} + Br{-}

Do I do start this with half reactions

Thanks

  1. 👍
  2. 👎
  3. 👁
  1. I always revert to half reactions when I have trouble. Most students forget to compare apples with applies; i.e., you should make that 2Br^ on the right to sstart. But let's do try this way.
    Cr is +3 on the left and +6 on the right so a gain of 3e.
    Br is zero on the left and 2Br^- is -2 on the right or a loss of 2. Cr x 2 and Br x 3 gives
    2Cr(OH)3 + 3Br2 ==> 2CrO4^2- + 6Br^-

    The charge on the right is -10 and zero on the left so add 10 OH to the left.
    10 OH^- + 2Cr(OH)3 + 3Br2 ==> 2CrO4^2- + 6Br^-.

    On the left there are 16H so on the right place 8 H2O
    10 OH^- + 2Cr(OH)3 + 3Br2 ==> 2CrO4^2- + 6Br^- + 8H2O

    See if that checks. It looks ok to me.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    Complete and balance the equation for this reaction in basic solution? Redox reaction Cr is oxidized to CrO42– and Fe3 is reduced to Fe2...? For a particular redox reaction Cr is oxidized to CrO42– and Fe3 is reduced to Fe2 .

  2. chemistry help

    For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants? 2Na(s)+Br2(g) ---->2NaBr(s) 1. 2mol Na, 2mol Br2 2. 1.8mol Na, 1.4mol Br2 3. 2.5mol Na, 1mol Br2 4. 12.6mol Na, 6.9 mol Br2

  3. chemistry

    In a particular redox reaction, Cr is oxidized to CrO4^2– and Cu2^+ is reduced to Cu^+ . Complete and balance the equation for this reaction in acidic solution. Cr + Cu^2+ ---> CrO4^2-+ Cu^+ i started off by doing this 2 x

  4. chemistry

    Nitrosyl bromide decomposes according to the following equation. 2NOBr (g)(equilibrium arrow) 2NO (g) + Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained

  1. chemistry

    Balancing Redox Reaction in Basic Solution CN- + MnO-4 --> CNO- + MnO2 H2O + CN- --> CNO- + 2H +2e 3e + 4H + MnO4- --> MnO2 + 2H2O My confusion is with adding the OH- please explain

  2. Chemistry

    Balance the equation in aqueous basic solution: NO2-(aq) + Al(s) → NH3(aq) + AlO2-(aq) I know how to balance equations in acidic solutions, but I get lost doing the basic one, please help?

  3. Chemistry

    Balance the reaction using half reactions under BASIC conditions: Al + CrO4^-2 ---> Al(OH)3 + Cr(OH)3 I tried to solve this question and ended up with this: Here are the two half equations Al ---> Al(OH)3 CrO4^-2 ---> Cr(OH)3 For

  4. balanced equation

    ? MnO4– + ?H+ + ?C2O42– --> ?Mn2+ + ?H2O + ?CO2 what's the balanced equation? correct coefficients? is it 1MnO4- + 2H+ + 1C2O42- --> 1Mn2+ + 1H20 + 2CO2 ? c2042..? are you missing parenthesis somewhere? oh i see, no i believe

  1. chem

    I need help balancing this redox equation: H2O2 + Ni+2 --> H2O + Ni+3 in basic solution. Here's what I have so far: Ni+2 --> Ni+3 + 1e- H2O2 --> H2O I can't seem to make the second half-reaction balance. If you follow the rules

  2. Chemistry

    In basic solution, H2O2 oxidizes Cr+3 to Cro4^-2 and is reduced to OH-. What is the balanced equation?

  3. chemistry

    Use the equation below to answer the questions that follow. Br2 + Cl 2 ⎯→ 2BrCl a. How many moles of BrCl form when 2.74 mol Cl2 react with excess Br2? b. How many grams of BrCl form when 239.7 g Cl2 react with excess Br2? c.

  4. Chemistry Problem

    At 25 oC, Kc = 0.145 for the following reaction in the solvent CCl4. 2BrCl Br2 + Cl2 A solution was prepared with the following initial concentrations: [BrCl] = 0.0482 M, [Br2]= 0.0307 M, and [Cl2]= 0.0277 M. What will their

You can view more similar questions or ask a new question.