a car goes over a circular hill of 50m radius at a constant speed of 20m/sec . What is the force of the car on the 600N driver at the top of the hill.?
To find the force exerted on the driver at the top of the circular hill, we can use the concept of centripetal force. Centripetal force is the force that keeps an object moving in a circular path.
In this case, the car is moving in a circular path with a radius of 50m and a constant speed of 20m/sec. The driver experiences a force directed towards the center of the circle (centripetal force) that keeps them moving in the circular path.
We can calculate the centripetal force using the following formula:
Centripetal Force = (Mass of the car) x (Centripetal acceleration)
Since we are given the mass of the driver, we can use their weight as an approximation of their mass. Weight is the force exerted on an object due to gravity, and it can be calculated using the formula:
Weight = Mass x Gravity
In this case, we are given that the driver's weight is 600N. Since the force of gravity acts vertically downwards, the weight is equal to the force exerted by the driver on the car.
Now, to calculate the centripetal acceleration, we can use the formula:
Centripetal acceleration = (Velocity^2) / (Radius)
Plugging in the known values, we have:
Centripetal acceleration = (20m/sec)^2 / 50m
Centripetal acceleration = 400m^2/sec^2 / 50m
Centripetal acceleration = 8m/sec^2
Finally, we can calculate the centripetal force using the formula mentioned earlier:
Centripetal Force = (Mass of the car) x (Centripetal acceleration)
Centripetal Force = Weight x Centripetal acceleration
Centripetal Force = 600N x 8m/sec^2
Centripetal Force = 4800N
Therefore, the force of the car on the driver at the top of the hill is 4800N.