Pre-Calculus

Rewrite each quadratic equation in the form ax^2+bx+c=0. Then,use technology to solve each by graphing. ROund you answers to the nearest hundredth, where necessary.

a) 3x^2+30 = -19x

Answer: 3x^2+19x+30 Roots: x = -3

b) 6x^2= 25x-24

Answer: -6x^2+25x-24=0 Roots: x = 1.5

c) -33-23x=4x^2

Answer: 4x^2+23x+33 = 0 Roots: x=-2.75

Thanks!

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  1. It is considered "better form" to have your quadratics start with a positive x^2 term
    So for #2, I would write:
    6x^2 - 25x + 24 = 0 , (just switch all the signs, like multiplying by -1)

    Each of your roots satisfy your equations, but each of your quads should have a second root.
    Since I don't know which "technology" you are using, I don't know where you went wrong.

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  2. Thank you. I was using a TI-83 Calculator

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