write an equation of a circle with the given center and radius. center (–7 –3) and radius 13
= (x-h)^2 +(y-k)^2 =r^2
= (x+7)^2 +(y+3)^2 = 13^2
To write the equation of a circle with a given center and radius, we can use the standard form equation of a circle, which is:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) is the center of the circle, and r is the radius.
In this case, the center is (-7, -3), and the radius is 13.
Plugging these values into the equation, we get:
(x - (-7))^2 + (y - (-3))^2 = 13^2
Simplifying this equation, we have:
(x + 7)^2 + (y + 3)^2 = 169
Therefore, the equation of the circle with center (-7, -3) and radius 13 is (x + 7)^2 + (y + 3)^2 = 169.