Calculus

In the next questions, a particle is moving along a horizontal line according to the formula:
s=2t^4-4t^3+2t^2-1

a) the particle is moving right when
A. 0 is less than t is less than 1/2
B. t is greater than 0
C. t is greater than 1
D. 0 is less than t is less than 1/2, t is greater than 1
E. Never

b) the acceleration, a is increasing when
A. t is greater than 1
B. t is greater than 0.5
C. t is less than 0.211 or t is greater than .789
D. 0 is less than t is less than 0.5
E. 0 is less than t is less than 1

  1. 👍
  2. 👎
  3. 👁
  1. moving right when s is increasing. That is, when ds/dt > 0

    a is increasing when da/dt is positive. That is,

    48t-24 > 0
    t > 2

    1. 👍
    2. 👎
  2. t is greater than 0.5, not 2

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. AP Calculus

    A particle moving along x-axis has velocity v(t) = sin(4t) at time t. If the particle is at x=4 when t=0, determine the position of the particle when t=pi/2.

  2. Calculus

    The velocity function (in meters per second) is given for a particle moving along a line. v(t) = 3t − 7, 0 ≤ t ≤ 3 (a) Find the displacement. -7.5 m (b) Find the distance traveled by the particle during the given time

  3. math

    The acceleration of a particle at a time t moving along the x-axis is give by: a(t) = 4e^(2t). At the instant when t=0, the particle is at the point x=2, moving with velocity v(t)=-2. Find the position of the particle at t=1/2 if

  4. Calculus

    The position of a particle moving along the x-axis at time t > 0 seconds is given by the function x(t) = e ^ t - 2t feet. a) Find the average velocity of the particel over the interval [1,3]. b) In what direction and how fast is

  1. AP Calculus

    A particle is moving along a horizontal straight line. The graph of the position function (the distance to the right of a fixed point as a function of time) is shown below. Answer the following questions only on the interval

  2. math

    The velocity function, in feet per second, is given for a particle moving along a straight line. v(t) = 3t − 2, 0 ≤ t ≤ 3 Find the displacement 15/2 Find the total distance that the particle travels over the given interval

  3. Calculus

    The velocity function is v(t)=t^2-5t+6 for a particle moving along a line. Find the displacement of the particle during the time interval [-3,6].

  4. physics

    Initially, a particle is moving at 5.45 m/s at an angle of 38.5° above the horizontal. Four seconds later, its velocity is 6.24 m/s at an angle of 54.3° below the horizontal. What was the particle's average acceleration during

  1. calculus

    A particle is moving along the curve below. y = sqrt(x) As the particle passes through the point (4,2), its x-coordinate increases at a rate of 4 cm/s. How fast is the distance from the particle to the origin changing at this

  2. calculus

    5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? Why? b. Find the acceleration of the particle at time t= 1.5. Is

  3. physics

    Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, act on a particle of mass 2.10 kg that is initially at rest at coordinates (−2.30 m, −3.60 m). (a) What are the components of the particle's velocity at t = 11.8 s?

  4. physics

    A 1.6 kg particle moving along the x-axis experiences the force shown in the figure. The particle's velocity is 4.2 m/s at x = 0 m. The figure or graph has F (N) along the y axis and velocity along the x axis. A diagonal line

You can view more similar questions or ask a new question.