Calculus

Find the exact real solutions, if any, of this quadratic equation. Use any method. If there is no real solution enter NONE in each box.

2x^2-5x+3=0

Is the smaller value none andthe larger value none.

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asked by George
  1. Use the quadratic formula

    x = [-b +/- sqrt(b^2-4ac)]/2a
    if you do not see how to factor it.

    Note that b^2-4ac = 1, so there are real solutions.

    This is not a calculus question. it is algebra.

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    posted by drwls

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