(-2x^2y)^3*(5xy^3)^2=(-2x^2y)^3 = -8 x^6 y^3

What did you do with the (5xy^3)^2 part. The first part you did ok. But you can't just throw away part of the equation.

I don't get that part.What do I do there.?

(5xy^3)^2=25x^2y^6
You did the first part ok by cubing it. I don't understand why you didn't do this part and square it. Such is life, I guess.

then I just multiply right.?

right.

ok so will it be:-200x^8y^9

right.

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