I need help checking my answer. I wasn't sure if 8 and 8 were both side lenegth's or if 22 is the slant height but I think it is got kind of confused there also wasn't sure how I was suppose to solve it but I sloved the problem how I though it was suppose to be sloved I have to different ways with two different answers.
find the lateral area of a square pyramid. with the two side lenegth's as 8 and 8 and the slant height as 22.
my answer 1. 8x4 = 32
32x22 = 704
704÷2 = 352
my answer 2. 8x8 = 64
64x22 = 1408
1408÷2 = 704
Im not rlly sure which 1 is right.
plz help me
Drop an altitude from the vertex to the center of the base. Now draw a line from there to the center of a side of the base. Seen from the side, you now have a right triangle with legs 4 and 22. The hypotenuse is the slant height of the pyramid, and thus the altitude of one of the triangular faces.
the slant height is √(4^2+22^2) = √500 = 10√5
So, the lateral area is 4 triangles with base 8 and height 10√5
4*(8*10√5)/2 = 160√5
The area of the pyramid is not 1/2 Bh. The area of each face is 1/2 bh, as calculated above.