Chemistry

Calculate the pOH of a 0.410 M Ba(OH) solution.

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  1. OH is 2x Ba(OH)2.
    pOH = -log(OH^-)

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  2. 8.62*10^-2

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  3. pOH = -log([OH])
    [OH]=concentration*# of hydroxide ions
    pOH=-log(2*0.41)
    pOH=8.62*10^-2

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