a boy pushes a shopping trolley weight due to gravity of 150n with a constant force of 75n.a constant force of 20n is present.draw labeled force diagram to identify all the force acting on the shopping trolley.
i think your gonna have to draw that one on ur own
To draw the labeled force diagram for the shopping trolley, we need to identify and label all the forces acting on it.
1. Weight due to gravity (W): This force is always present and acts vertically downward. Given that the weight due to gravity is 150N, draw an arrow pointing downward from the center of the trolley and label it as "W" with a magnitude of 150N.
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W (150N)
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2. Force applied by the boy (Fboy): The boy applies a force of 75N to push the trolley. This force acts in the direction of the push. Draw an arrow pointing in the direction of the push from the center of the trolley and label it as "Fboy" with a magnitude of 75N.
----> Fboy (75N)
3. Normal force (N): The normal force refers to the force exerted by a surface to support the weight of an object resting on it. In this case, the trolley is on a flat surface, and the normal force will act perpendicular to it. The magnitude of the normal force is equal to the weight due to gravity. Draw an arrow pointing vertically upward from the center of the trolley and label it as "N" with a magnitude of 150N.
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N (150N)
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4. Friction force (Ffric): The friction force acts opposite to the direction of motion or attempted motion between the surfaces in contact. Since a constant force of 20N is present, this force is the friction force. Draw an arrow pointing opposite to the direction of the push from the center of the trolley and label it as "Ffric" with a magnitude of 20N.
<---- Ffric (20N)
The force diagram for the shopping trolley is now complete, showing all the labeled forces acting on it.
To draw a labeled force diagram for the shopping trolley, we need to identify all the forces acting on it based on the given information. Let's break it down:
1. Weight due to gravity (W):
The weight of the shopping trolley is given as 150 N. Gravity always acts downwards, so we represent it as a downward arrow labeled W or 150 N.
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W=150N
2. Pushing force applied by the boy (F1):
The boy pushes the trolley with a constant force of 75 N in a certain direction. This force helps to move the trolley forward, so we represent it as an arrow in the direction of motion. Label it as F1 or 75 N.
------> F1=75N
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W=150N
3. Frictional force opposing motion (F2):
A constant force of 20 N is present, which opposes the motion of the trolley. This is the frictional force acting in the opposite direction to the pushing force. We represent it as an arrow in the opposite direction with the label F2 or 20 N.
<--- F2=20N
------> F1=75N
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W=150N
These are the labeled forces acting on the shopping trolley: weight (W), pushing force (F1), and frictional force (F2).