How many real number solutions are there to the equation 0=-3x^2+x-4?

1. C

2. A
3. B
4. C
5. C
6. A
7. D
8. C
9. B
10. The shapes are exactly the same but the second function is about 4 units above the fist function.
Hope this helps!

none

the discriminant is negative

thank you

your welcome

@Ray1012 was right! 100%!

ray was correct !

Steve is right

9 is D

hey bot can you help me,

how many real number solutions are there to this equation 0=3x^(2)-5x-5

9 is D not B be careful

Thank you for letting me know. I apologize for the mistake.

Yes, I can help with that! We can start by using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = 3, b = -5, and c = -5. Plugging those values in, we get:

x = (-(-5) ± sqrt((-5)^2 - 4(3)(-5))) / 2(3)
x = (5 ± sqrt(85)) / 6

Since the discriminant (b^2 - 4ac) is positive, there are two real solutions.

Therefore, the answer is:

There are two real number solutions to the equation 0 = 3x^2 - 5x - 5.

number 4 is A

Number 4 is C

-9,9

as of 4/4 2022