Physics

A battery has an emf of 15.0 V. The terminal voltage of the battery is 11.2 V when it is delivering 26.0 W of power to an external load resistor R.

(a) What is the value of R?

(b) What is the internal resistance of the battery?

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  1. The volts across your load resistor = 11.2V
    Power delivered = 26.0 W
    Power = Volts x Amps so Current (Amps) = 26.0/11.2 V = 2.32A

    (A) 11.2V/2.32A = 4.83 ohm

    Volts lost across internal resistance = 15 - 11.2 = 3.8V

    Internal resistance = Lost Volts/Current = 3.8/2.32 = 1.64 ohms (B)

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