Physics

Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 9.8 W. While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains unchanged.

Answer:
V^2/watts = ohms
V^2/ohms + V^2/2(ohms) = W

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  1. power = V^2/Req = 9.8 = 26^2/Req
    so
    Req = 69 ohms
    so R = 2 Req = 138 Ohms

    new Req:
    1/Req = 1/138 + 1/276
    Req = 92 Ohms

    power = 26^2/92 = 7.35 Watts

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    posted by Damon

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