Introductory Algebra

the length of a rectangle is 7 meters more than twice the width. the perimeter is 68 meters. solve for length and width.

I need this step by step using the blueprint...please.

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  1. No blueprint available.

    L = 2W + 7

    2W + 2L = 68

    Substitute 2W+7 for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.

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  2. 150

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  3. he length of a rectangle is 7 meters more than twice the width. the perimeter is 68 meters. solve for length and width.

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