math

How do i find the perimeter of a triangle with variables?

one side is 2(q^2 - 3q), the second side is q + 10 and the third side is q^2.

how do i add all of these sides

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  1. 2(q^2-3q) = 2q^2-6q
    So, you want to add up

    2q^2-6q+q+10+q^2

    Keep like powers together, and you end up with

    (2+1)q^2 + (=6+1)q + 10
    3q^2-5q+10

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    posted by Steve

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