physics

a basketball player tries to make a half court jumpshot releasing the ball at the height of the basket assuming the ball is lunch at 51 degrees 14 meters from the basket what velocity musta player give the ball

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  1. the range of the ball is

    R = (v^2 sin2θ)/g

    so just find v such that

    (v^2 sin(102°))/9.8 = 14

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