Can someone please help me solve this problem?
If the probability of a baseball player's getting it in one time at bat is 0.326, find the probability that the player gets no hits in 4 times at bat.
Thank you!
Sure, I can help you with that! To find the probability that the player gets no hits in 4 times at bat, we need to use the concept of independent events in probability.
The probability of getting a hit in one time at bat is given as 0.326. Therefore, the probability of not getting a hit in one time at bat is the complement of that, which is 1 - 0.326 = 0.674.
Since the events of getting a hit or not getting a hit in each at-bat are assumed to be independent, we can multiply the probabilities of not getting a hit in all four at-bats.
So, the probability of not getting a hit in four times at bat is (0.674)^4 ≈ 0.183.
Therefore, the probability that the player gets no hits in 4 times at bat is approximately 0.183, or 18.3%.
I hope that helps! Let me know if you have any further questions.