MATH

THE FIRST AND LAST TERMS OF AN ARITHMETIC SERIES IS 5 AND 61 RESPECTIVELY WHILE THE SUM OF ALL THE TERMS IS 957. DETERMINE THE NUMBER OF TERMS IN THE SERIES.

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  1. If there are n terms,

    n/2 (5+61) = 957
    n = 29

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  2. a = 5
    last term = 61

    sum(n) = (n/2)(first + last)
    957 = (n/2)(5 + 61)
    1914 = 66n
    n =29

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