Question 1:A child's wagon with a mass of 11 kg is moving at a constant speed of 4 m/s on a horizontal frictionless surface at the Houston Zoo. After a 4.2 kg Southern Ground Hornbill lands by vertical descent in the child's wagon, the velocity of the wagon will be Answer m/s.
Question 2: A child's wagon with a mass of 19 kg is moving at a constant speed of 2 m/s on a horizontal frictionless surface at the Houston Zoo. When a 4.2 kg Southern Ground Hornbill lands by vertical descent in the child's wagon, the momentum of the wagon and the hornbill will be AnswerIncorrect kg m/s.
~ I know these are the same type of questions.... I just don't understand momentum...~
momentum is conserved. In this case, we are considering only the horizontal motion, since the wagon cannot move vertically.
So, the basic problem is that of what happens when the wagon's mass is suddenly increased by the addition of the bird's mass.
To conserve momentum, the new larger mass has to slow down. Momentum is mass * velocity, so
11*4 = (11+4.2)v
Now just solve for v.
Question 1: Ah, the Houston Zoo, where even birds can't resist hitching a ride! Well, let's calculate that momentum shift. The initial momentum of the wagon, with a mass of 11 kg and velocity of 4 m/s, is 44 kg m/s (p = m * v). After the 4.2 kg Southern Ground Hornbill lands, we add its momentum, which can be calculated as (mass of the bird * velocity of the bird). However, since the bird is landing in a vertical descent, its velocity is not given, so we can't determine the final velocity of the wagon. Sorry, I can't clown around with this one.
Question 2: Alrighty, let's solve another momentum mystery at the Houston Zoo! The initial momentum of the wagon, with a mass of 19 kg and velocity of 2 m/s, is 38 kg m/s (p = m * v). When the 4.2 kg Southern Ground Hornbill lands, we add its momentum, which is (mass of the bird * velocity of the bird). Unfortunately, you didn't provide the velocity of the bird, so I can't calculate the final momentum. Looks like this mystery remains unsolved!
To answer these questions, we need to use the principle of conservation of momentum. Momentum is given by the equation:
Momentum (p) = mass (m) × velocity (v)
According to the principle of conservation of momentum, the total momentum before and after an event remains constant unless an external force acts on the system. Therefore, we can calculate the final velocity of the wagon in these scenarios.
Question 1:
Before the Southern Ground Hornbill lands in the wagon, the total momentum is the product of the mass of the wagon (11 kg) and its velocity (4 m/s):
Initial momentum = 11 kg × 4 m/s = 44 kg∙m/s
After the bird lands in the wagon, the total momentum would be the sum of the initial momentum and the product of the bird's mass (4.2 kg) and the final velocity of the wagon (which we need to find):
Final momentum = (11 kg + 4.2 kg) × final velocity
Since momentum is conserved, the initial momentum and the final momentum should be equal:
44 kg∙m/s = (11 kg + 4.2 kg) × final velocity
Simplifying the equation:
44 kg∙m/s = 15.2 kg × final velocity
Solving for the final velocity:
final velocity = 44 kg∙m/s / 15.2 kg = 2.89 m/s
Therefore, the velocity of the wagon after the Southern Ground Hornbill lands will be approximately 2.89 m/s.
Question 2:
Similarly, before the bird lands in the wagon, the total momentum is:
Initial momentum = 19 kg × 2 m/s = 38 kg∙m/s
After the bird lands in the wagon, the total momentum would be:
Final momentum = (19 kg + 4.2 kg) × final velocity
Using the principle of conservation of momentum:
38 kg∙m/s = (19 kg + 4.2 kg) × final velocity
Simplifying:
38 kg∙m/s = 23.2 kg × final velocity
Solving for the final velocity:
final velocity = 38 kg∙m/s / 23.2 kg = 1.64 m/s
Therefore, the momentum of the wagon and the hornbill will be 1.64 kg∙m/s after the bird lands.
To answer these questions, you need to understand the concept of momentum. Momentum is defined as the product of an object's mass and velocity. It is a vector quantity, meaning it has both magnitude and direction.
Question 1:
To find the answer, we need to use the principle of conservation of momentum. According to this principle, when two objects interact, their total momentum remains constant, provided no external forces act on them.
In this case, we have a child's wagon initially moving at a constant speed of 4 m/s. The wagon has a mass of 11 kg. When the Southern Ground Hornbill, which has a mass of 4.2 kg, lands by vertical descent in the wagon, we need to find the final velocity of the wagon.
Given:
Mass of the wagon (m₁) = 11 kg
Initial velocity of the wagon (v₁) = 4 m/s
Mass of the Hornbill (m₂) = 4.2 kg
Using the conservation of momentum principle, we can write:
(m₁ * v₁) + (m₂ * v₂) = (m₁ * v₁')
Solving for the final velocity of the wagon (v₁'), we get:
v₁' = [(m₁ * v₁) + (m₂ * v₂)] / m₁
Since the wagon is initially moving at a constant speed, its initial velocity (v₁) remains the same, which is 4 m/s. And we want to find the final velocity of the wagon, so we can rewrite the equation as:
v₁' = (m₁ * v₁ + m₂ * v₂) / m₁
Substituting the known values:
v₁' = (11 kg * 4 m/s + 4.2 kg * v₂) / 11 kg
Now we need to find the value of v₂, which is the final velocity of the Hornbill and is vertical downwards because of its vertical descent. Since only the wagon's velocity is given, we can assume that the Hornbill starts from rest (v₂ = 0 m/s).
v₁' = (11 kg * 4 m/s + 4.2 kg * 0 m/s) / 11 kg
v₁' = 44 kg * m/s / 11 kg
v₁' = 4 m/s
Therefore, the velocity of the wagon after the hornbill lands in it will remain 4 m/s.
Question 2:
To find the momentum of the wagon and the hornbill after the hornbill lands, we use the same principle of conservation of momentum.
Given:
Mass of the wagon (m₁) = 19 kg
Initial velocity of the wagon (v₁) = 2 m/s
Mass of the Hornbill (m₂) = 4.2 kg
Using the same equation as before:
(m₁ * v₁) + (m₂ * v₂) = (m₁ * v₁')
We want to find the momentum after the hornbill lands, which is the final momentum (p').
p' = m₁ * v₁' + m₂ * v₂
Substituting the known values:
p' = 19 kg * v₁' + 4.2 kg * v₂
However, without knowing the value of v₂, we can't determine the final momentum. So, we can't provide an exact answer in this case.
To summarize, in question 1, the velocity of the wagon after the hornbill lands is 4 m/s. In question 2, the momentum of the wagon and the hornbill after the landing cannot be determined without knowing the final velocity of the hornbill.