Estimate the rate of the reaction,
H2SeO3 + 6I^- + 4H^+ --> Se + 2I3^- + 3H2O
given that the rate law for the reaction at 0°C is
rate = (5.0 × 105 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2
The reactant concentrations are:
[H2SeO3] = 1.5 × 10-2 M
[I-] = 2.4 × 10-3 M
[H+] = 1.5 × 10-3 M
To estimate the rate of the reaction using the given rate law and reactant concentrations, we can simply substitute the given values into the rate law equation.
Given:
[H2SeO3] = 1.5 × 10-2 M
[I-] = 2.4 × 10-3 M
[H+] = 1.5 × 10-3 M
Substituting the values into the rate law equation:
rate = (5.0 × 105 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2
= (5.0 × 105 L5mol-5s-1)(1.5 × 10-2 M)(2.4 × 10-3 M)^3(1.5 × 10-3 M)^2
To simplify the calculation, let's convert the units into a more convenient form:
rate = (5.0 × 105 L5mol-5s-1)(1.5 × 10-2)(2.4 × 10-3)^3(1.5 × 10-3)^2
Calculating the numerical value of the rate:
rate = (5.0 × 105)(1.5 × 10-2)(2.4 × 10-3)^3(1.5 × 10-3)^2
To evaluate this expression, we can use a calculator or scientific notation:
rate ≈ 9.72 × 10-10 L5mol-5s-1
Therefore, the estimated rate of the reaction is approximately 9.72 × 10-10 L5mol-5s-1.