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chemistry

A solution of HClO is mixed and found to
have a pH of 4.53. Find what the initial
concentration of HClO was for this solution.
Ka = 3.00 × 10−8
for HClO.
Answer in units of mol/L

please help this is due in 1 hour

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  1. ka= 3.00 * 10 -8

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  2. pH = 4.53 = -log(H^+). Solve for (H^+) and that's approx 1E-5 but that's just close so you need to do it more accurately.
    .........HClO ==> H^+ + ClO^-
    I........x........0......0
    C.......-y........y.......y
    E........x-y......y........y

    The problem tells you (actually the (H^+) from above tells you y = 10^-5

    Ka = (H^+)(ClO^-)/(HClO)
    (H^+) = 1E-5
    (ClO^=) = 1E-5
    (HClO) = x-1E-5
    Solve for x.

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