chemistry

A 12.42 gram sample of a mixture of NaCl and CaCl2 is dissolved in water and all the chloride is precipitated as AgCl. If the AgCl precipitate has a mass of 31.70 grams. How do I find the mass percentage of each component in the original mixture?

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  1. You write two equations and solve them simultaneously. First equation is
    let x = mass NaCl
    and y = mass CaCl2
    ----------------------
    equation 1 is
    x + y = 12.42

    The second equation you get by converting x and y to grams AgCl
    For NaCl(x) that is
    x(mm AgCl/mm NaCl) where mm is molar mass.

    For CaCl2(y) that is
    y(mm CaCl2/2*mm AgCl)

    and you know total mass of AgCl is 31.70 so
    x(mm NaCl/mm AgCl) + y(mm CaCl2/2*mm AgCl = 31.70 g

    Solve for x and y, then
    % NaCl = (x/12.42)*100 = ?
    % CaCl2 = (y/12.42)*100 = ?

    Post your work if you get stuck.

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