Write an equation in point-slope form for the line that passes through one of the following pairs of points (you may choose the pair you want to work with). Then, use the same set of points to write the equation in standard form and again in slope-intercept form.

(5, 1) and (-3, 4).
The formula for it is: slope = rise/run
slope = 4 – 1 / -3 -5 = 3/-8
-3/8 is the slope.

Point slope form
y - 1 = -3 (x - 5)/8

Slope intercept form
y - 1 = -3x/8 + 15/8
y = -3x/8 + 23/8

Standard form
8y = -3x + 23

is this ok? pls help asap! thanks

looks good, except for the standard form. That would be

3x + 8y = 23

thank you Steven!:)

Can you help with the Johnny Tremain rising action question??

Yes, your equations are correct! Great job!

To find the equation in point-slope form, you first need to calculate the slope using the formula: slope = (y2 - y1) / (x2 - x1). In this case, the points are (5, 1) and (-3, 4). Plugging them into the formula, we get:

slope = (4 - 1) / (-3 - 5) = 3 / -8 = -3/8.

Next, you can use the point-slope form, which is: y - y1 = m(x - x1), where m is the slope and (x1, y1) is one of the given points. Choosing (5, 1) as our point, we can substitute the values into the formula:

y - 1 = -3/8 (x - 5).

To convert this equation to slope-intercept form (y = mx + b), we can simplify it:

y - 1 = -3/8x + 15/8.
y = -3/8x + 15/8 + 1
y = -3/8x + 23/8.

For the standard form of the equation, we need to get rid of any fractions. Multiply both sides of the slope-intercept form by 8 to eliminate the fraction:

8y = -3x + 23.

So, your equations, point-slope form, slope-intercept form, and standard form, are all correct!