Determine the magnitude of the gravitational force Mars would exert on man if he was on the surface of Mars. The mass of the man is 69.0kg . The mass of the Mars is 6.42×1023kg and its radius is 3396 km.
To determine the magnitude of the gravitational force Mars would exert on a man on its surface, we can use Newton's law of universal gravitation:
F = (G * m1 * m2) / r^2
Where:
F is the gravitational force
G is the gravitational constant (approximately 6.674 × 10^-11 N*m^2/kg^2)
m1 is the mass of the man (69.0 kg)
m2 is the mass of Mars (6.42 × 10^23 kg)
r is the radius of Mars (3396 km or 3,396,000 meters)
Let's plug in the values:
F = (6.674 × 10^-11 N*m^2/kg^2 * 69.0 kg * 6.42 × 10^23 kg) / (3396,000 meters)^2
Simplifying:
F = (6.674 × 10^-11 N*m^2/kg^2 * 69.0 kg * 6.42 × 10^23 kg) / (11,527,616,000,000 meters^2)
Calculating:
F ≈ 1.78 × 10^23 N
Therefore, the magnitude of the gravitational force Mars would exert on a man on its surface is approximately 1.78 × 10^23 Newtons.
To determine the magnitude of the gravitational force Mars would exert on a man on its surface, we can use the formula for gravitational force:
F = (G * m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.67 × 10^-11 N m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two objects.
Given:
Mass of the man (m1) = 69.0 kg
Mass of Mars (m2) = 6.42 × 10^23 kg
Radius of Mars (r) = 3396 km = 3396 × 10^3 m
First, we need to convert the radius of Mars to meters to maintain consistent units:
r = 3396 × 10^3 m
Now we can substitute the values into the formula:
F = (6.67 × 10^-11 N m^2/kg^2 * 6.42 × 10^23 kg * 69.0 kg) / (3396 × 10^3 m)^2
Calculating this expression will give us the magnitude of the gravitational force Mars would exert on a man on its surface.