A block of mass 4 kg slides down a frictionless inclined plane angled 30 degrees above the horizontal. The force accelerating the block down the plane is thus:
a. zero, since there is no friction
b. 9.8N
c. 19.6N
d. 33.9N
e. 39.2N
m g sin theta
4 * 9.81 * (1/2)
about 19.6 N
The force accelerating the block down the plane can be determined using the formula:
Force = Mass * Acceleration
Since the inclined plane is frictionless, the only force acting on the block is the component of the gravitational force along the plane. This force can be calculated using the formula:
Force = Mass * Gravity * sin(angle)
Given that the mass of the block is 4 kg, the acceleration due to gravity is 9.8 m/s^2, and the angle of the inclined plane is 30 degrees, we can substitute these values into the formula:
Force = 4 kg * 9.8 m/s^2 * sin(30 degrees)
Force = 4 kg * 9.8 m/s^2 * 0.5
Force = 19.6 N
Therefore, the correct answer is c. 19.6N.
To determine the force accelerating the block down the inclined plane, we need to consider the force components acting on the block.
First, let's resolve the force of gravity into its components. The force of gravity acting on the block can be represented by its weight, which is given by the equation: weight = mass * acceleration due to gravity.
Weight = 4 kg * 9.8 m/s^2 = 39.2 N
Next, we need to find the force component of the weight that acts in the direction of the inclined plane. This force is equal to the weight multiplied by the sine of the angle of inclination (30 degrees).
Force component acting down the plane = 39.2 N * sin(30°) = 19.6 N
Therefore, the force accelerating the block down the plane is 19.6 N.
The correct answer is c. 19.6 N.