The height H and beat of a ball after T seconds is given by H equals 80t team take away 16x2. how long did it take for the bout to hit the ground
In English please.
have you considered taking a typing class?
You want to find when the height h:
80t - 16t^2 = 0
16t(5-t) = 0
I think it's clear now when h=0. (Just in case you haven't figured it out, the ball hits the ground when the height is zero...)
To find out how long it took for the ball to hit the ground, we need to set H (height) equal to zero.
The given equation is H = 80t - 16t^2, where H is the height and t is the time in seconds.
Setting H equal to zero:
0 = 80t - 16t^2
This is a quadratic equation. We can solve it by factoring or by using the quadratic formula.
To solve by factoring, we need to rewrite the equation in the standard form:
16t^2 - 80t = 0
Factoring out common factor t:
t(16t - 80) = 0
Now we have two factors:
t = 0 or 16t - 80 = 0
The first factor, t = 0, represents the height at the start when t = 0. We can ignore this solution since we are interested in when the ball hits the ground.
Solving the second factor:
16t - 80 = 0
16t = 80
t = 80/16
t = 5
Therefore, it took 5 seconds for the ball to hit the ground.