# Chem Moles

Use this equation: N2 + 3 H2 ---> 2 NH3

If 3.00 moles of H2 were used, how many moles of NH3 would be made?

If 0.600 moles of NH3 were produced, how many moles of H2 are required?

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1. All of this type question are solved by the factor method using the coefficients as factors. Here is the first one; you see if you can do the second one.
3.00 mols H2 x (2 mols NH3/3 mols H2) = 3.00 x 2/3 = 2.00 mols NH3 produced.

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2. i still don't understand the second
@DrBob222

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3. N2 + 3H2 ==> 2NH3
We have 3.0 mols H2. We can convert that to any thing with the proper factor. The factor is made using the coefficients in the balanced equation.
3.0 mol H2 x factor = mols NH3.
3.0 mols H2 x (2 mol NH3/3 mol H2) = ?
See that mol H2 cancel and leaves mol NH3 which is what you wanted. So what you want to convert TO goes on top and what you are converting FROM goes on the bottom. So 3.0 x 2/3 = 2 mol NH3 produced.
How much N2 was used?
3.0 mols H2 x (1 mol N2/3 mols H2) = 3.0 x 1/3 = 1.0 mol N2 used.
To convert anything to anything it's the
known value x (factor) = new value or
know value x (to/from) = ?

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4. just tell me the answer

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