An award is being plated with pure gold before it its presented to a recipient. If the area of the award is 55.0 cm^3 and will be plated with 3.00 micrometers of Au, what mass of Au will be plated on the award? The density of Au is 19.3 g/cm^3.
AREA is NOT in cm^3 but in cm^2
Should I trust the rest of what you tyoed?
Oh well
3 * 10^-6 meters(10^2 cm/m) = 3*10^-4 cm
3*10^-4 * .55*10^2 = 1.65*10^-2 cm^3
19.3 g/cm^3 * 1.65*10^-2 cm^3 = .318 g
So the volume will be area x thickness = 55 cm x 3E-4 cm = ?
mass = volume x density = ?
this is what was on my worksheet
To find the mass of the gold plated on the award, we can use the formula:
Mass = Volume × Density
First, we need to calculate the volume of the gold plated. Given that the area of the award is 55.0 cm^3 and it will be plated with 3.00 micrometers of gold, we need to convert micrometers to centimeters before calculating the volume.
1 micrometer = 1 × 10^-4 cm
Therefore, 3.00 micrometers = 3.00 × 10^-4 cm
The thickness of the gold layer is now in centimeters.
To calculate the volume, we use the formula:
Volume = Area × Thickness
Volume = 55.0 cm^3 × 3.00 × 10^-4 cm
Now we can substitute the calculated volume and density into the formula to find the mass:
Mass = Volume × Density
Mass = (55.0 cm^3 × 3.00 × 10^-4 cm) × 19.3 g/cm^3
After substituting the values and calculating, we find that the mass of the gold plated on the award is approximately 3.16 grams.