An arithmetic sequence has first term of 6 and difference of 8; what is the tenth term?
a10(subscript 10) = ?
a10 = 6 + 9*8
To find the 10th term of an arithmetic sequence, you can use the formula:
a_n = a_1 + (n - 1)d
Where:
a_n is the nth term (in this case, the 10th term).
a_1 is the first term.
d is the common difference between terms.
Given that the first term, a_1, is 6 and the common difference, d, is 8, you can substitute those values into the formula to find the 10th term:
a_10 = 6 + (10 - 1) * 8
Simplifying the equation:
a_10 = 6 + 9 * 8
a_10 = 6 + 72
a_10 = 78
Therefore, the 10th term of the arithmetic sequence with a first term of 6 and a difference of 8 is 78.
To find the tenth term of an arithmetic sequence, you can use the formula:
a(n) = a(1) + (n - 1) * d
Where:
a(n) is the nth term of the arithmetic sequence,
a(1) is the first term of the sequence,
n is the position of the term you want to find,
d is the common difference between consecutive terms.
Given that the arithmetic sequence has a first term (a(1)) of 6 and a difference (d) of 8, you can substitute these values into the formula:
a(10) = 6 + (10 - 1) * 8
Simplifying the equation:
a(10) = 6 + 9 * 8
a(10) = 6 + 72
a(10) = 78
Therefore, the tenth term of the arithmetic sequence is 78.