Calculate the torque produced by a force of 50.0 N applied clockwise perpendicular to the end of a bar of length 0.50 m.
Perpendicular torque is t = Force*length of lever
So t = 50*.5 = 25 Nm clockwise
To calculate the torque produced by a force, we can use the formula:
Torque = Force x Distance x sin(θ)
Where:
- Torque is the torque produced by the force
- Force is the magnitude of the applied force
- Distance is the perpendicular distance from the point of rotation to the line of action of the force
- θ is the angle between the force and the lever arm
In this case, the force applied is 50.0 N and it is applied perpendicular to the end of a bar of length 0.50 m. Since the force is applied perpendicularly, the angle θ is 90 degrees.
Plugging the values into the formula:
Torque = 50.0 N x 0.50 m x sin(90°)
Since sin(90°) equals 1, the equation simplifies to:
Torque = 50.0 N x 0.50 m x 1
Finally, we can calculate the torque:
Torque = 25.0 Nm
Therefore, the torque produced by this force is 25.0 Newton-meters (Nm) clockwise.
To calculate the torque produced by a force applied perpendicular to a lever arm, you can use the formula:
Torque = Force x Lever Arm
In this case, the force applied is 50.0 N and the lever arm is 0.50 m. Simply multiply the force by the lever arm to find the torque:
Torque = 50.0 N x 0.50 m
= 25.0 N⋅m
So, the torque produced by the force of 50.0 N applied clockwise perpendicular to the end of a bar of length 0.50 m is 25.0 N⋅m.