# Math

prove:
1/log(base36)a = 2/log(base6)a

i made a common base and then multiplied both sides with log(base6)a to get
2=log(base6)a/log(base6^2)a but this is as far as i can figure.

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1. since 36=6^2

its exponents are only half as big as powers of 6 to get to the same value. That is,

log_36(n) = 1/2 log_6(n)

So,

1/log_36(a) = 1/ (1/2 log_6(a)) = 2/log_6(a)

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posted by Steve

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