Determine the percent by mass of water in your sample of hydrated copper (II) sulfate - CuSO4. xH2O
My work
I got 10% is this correct?
No. See your later post way up the page.
To determine the percent by mass of water in the sample of hydrated copper (II) sulfate, you need to know the molar mass of water and the molar mass of copper (II) sulfate. Let's break down the steps to find the answer:
1. Calculate the molar mass of water (H2O):
- The molar mass of hydrogen (H) is approximately 1 g/mol.
- The molar mass of oxygen (O) is approximately 16 g/mol.
- Multiply the molar mass of hydrogen by 2 and add it to the molar mass of oxygen: (2 * 1) + 16 = 18 g/mol.
2. Determine the molar mass of hydrated copper (II) sulfate (CuSO4.xH2O):
- The molar mass of copper (Cu) is approximately 63.5 g/mol.
- The molar mass of sulfur (S) is approximately 32 g/mol.
- The molar mass of oxygen (O) is approximately 16 g/mol.
- Multiply the molar mass of oxygen by 4 and add it to the sum of the molar masses of copper and sulfur: (4 * 16) + 63.5 + 32 = 160.5 g/mol.
Note: The value of x represents the number of water molecules associated with one formula unit of CuSO4. Therefore, you need to find the value of x.
3. Using the information provided, find the value of x:
- Divide the molar mass of water (18 g/mol) by the molar mass of hydrated copper (II) sulfate (160.5 g/mol).
- Multiply the result by 100 to obtain the percentage: (18/160.5) * 100 = 11.2%.
Hence, the percent by mass of water in your sample of hydrated copper (II) sulfate is approximately 11.2%, not 10%.