math

The 3rd term of a geometric progression is nine times the first term.if the second term is one-twenty fourth the 5th term.find the 4th term. solution ar^2=9a r=sqr of 9 r=3.pls help me on how to get the first term(a)

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  1. ar^2 = 9a
    so, r = ±3

    Now we have a problem. We know that r=3, so the 5th term must be 27 times the 2nd term, regardless of the value of a.

    And, as you say, there is no way to determine a from the information given so far.

    You sure it's not 24 less than the 5th term?

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  2. Pls show work in details.

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