In the roasting of zinc ore, the total enthalpy for the reactants is -412.0 kJ and the total enthalpy for the products is -1294.54 kJ. What is the enthalpy for the roasting reaction?

A. 882.54 kJ
B. -1706.54 kJ
C. 1706.54 kJ
D. -882.54 kJ

I think the answer is d.

Answer is D. E=Products-Reactants

To find the enthalpy for the roasting reaction, we can use the equation:

ΔH = ΣΔH(products) - ΣΔH(reactants)

Given that the total enthalpy for the reactants is -412.0 kJ and the total enthalpy for the products is -1294.54 kJ, substituting these values into the equation:

ΔH = -1294.54 kJ - (-412.0 kJ)
ΔH = -1294.54 kJ + 412.0 kJ
ΔH = -882.54 kJ

Therefore, the enthalpy for the roasting reaction is -882.54 kJ, which corresponds to option D.

To find the enthalpy for the roasting reaction, we need to calculate the difference between the total enthalpy of the products and the total enthalpy of the reactants.

The total enthalpy for the reactants is given as -412.0 kJ, and the total enthalpy for the products is given as -1294.54 kJ.

To find the enthalpy of the reaction, we can subtract the total enthalpy of the reactants from the total enthalpy of the products:

Enthalpy of the roasting reaction = Total enthalpy of the products - Total enthalpy of the reactants
= -1294.54 kJ - (-412.0 kJ)
= -1294.54 kJ + 412.0 kJ
= -882.54 kJ

Therefore, the correct answer is D. -882.54 kJ.