Mr. Rahim had the same amount of money in his three bank accounts at first. He deposited $44 into account b and $ 80 into account c. In the end, the ratio of the amount of money in account a to the amount of money in account c was 2:7. How much money was there in account b in the end?
34
5:3
To solve this problem, we need to use algebraic reasoning and set up equations based on the given information.
Let's assume Mr. Rahim had x amount of money in each account at first.
After depositing $44 into account b, the amount of money in account b is now x + $44.
After depositing $80 into account c, the amount of money in account c is now x + $80.
Given that the ratio of the amount of money in account a to the amount of money in account c is 2:7, we can set up the following equation:
(amount in account a) / (amount in account c) = 2/7
Substituting the respective values, we get:
x / (x + $80) = 2/7
To solve for x, we can cross-multiply:
7x = 2(x + $80)
7x = 2x + $160
Subtracting 2x from both sides:
5x = $160
Dividing both sides by 5:
x = $32
Now we know that Mr. Rahim initially had $32 in each account.
To find out how much money was there in account b in the end, we add $44 to the initial amount in account b:
Amount in account b = $32 + $44 = $76
So, there was $76 in account b in the end.