Carina has twice as many quarters as dimes. If she has $3.60,
how many quarters does she have?
q = 2d
25q+10d = 360
q = 2 d
.25 q + .10 d = 3.6
.25(2 d) + .1 d = 3.6
.6 d = 3.6
6 d = 36
d = 6
so q = 12
To solve this problem, we need to set up an equation based on the given information.
Let's assume Carina has x dimes. According to the problem, she has twice as many quarters as dimes, so she would have 2x quarters.
Now, let's convert the number of dimes and quarters into their respective values. One dime is equal to $0.10, so x dimes would be worth 0.10x dollars. One quarter is equal to $0.25, so 2x quarters would be worth 0.25 * 2x = 0.50x dollars.
The problem says that Carina has a total of $3.60, so we can set up an equation:
0.10x + 0.50x = 3.60
Simplifying the equation, we have:
0.60x = 3.60
Dividing both sides by 0.60:
x = 3.60 / 0.60
x = 6
Since x represents the number of dimes, Carina has 6 dimes. And since she has twice as many quarters, she must have 2 * 6 = 12 quarters.
Therefore, Carina has 12 quarters.