a cylindrical wire of lenght 2.80m and a radius of 1.35A, when the voltage of 0.0320v is applied across the ends of the wire. from what material is the wire made of?
need radius of wire, not just current
R = V/i = .0320/1.35 = .0237 Ohms
= resistivity * Length/area
so resistivity = .0237 * pi r^2 /2.8
table of conductivity and resistivity here
http://hyperphysics.phy-astr.gsu.edu/hbase/tables/rstiv.html
To determine the material of the wire, we can use the formula for resistance: R = (ρ * L) / A, where R is the resistance, ρ (rho) is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
However, in this case, we need to rearrange the formula to solve for the resistivity ρ. The rearranged formula is: ρ = (R * A) / L.
Given:
Length of the wire (L) = 2.80 m
Radius of the wire (r) = 1.35 Å (Angstroms)
Voltage across the wire (V) = 0.0320 V
To apply the formula, we need to convert the radius from Angstroms to meters:
1 Å = 1 x 10^-10 m
So, the radius (r) = 1.35 x 10^-10 m
Now, we can calculate the area (A) of the wire:
A = π * r^2
= π * (1.35 x 10^-10)^2
Next, we need to calculate the resistance (R) using Ohm's Law:
R = V / I (where I is the current, which is not given in this question)
Since we are not given the current, we cannot directly calculate the resistance. Therefore, we cannot specifically determine the resistivity (ρ) and, consequently, the material of the wire without additional information, such as the current flowing through the wire.