Ok so I did what you told me reiny but I cant figure out number three which is here
10x - 2 - 6x = 3x - 2 + x
Please show how You did it please?
4x-2=4x-2
0=0
So there is no solution?
Did you not read the 3 conditions I outlined for you?
Especially this one:
"- if the variable drops out, and you get a true statement, there will be an infinite number of solutions "
so you got 0=0, which is true, thus there will be an infinite number of solutions
To solve the given equation, 10x - 2 - 6x = 3x - 2 + x, we need to simplify both sides of the equation by combining like terms.
Let's start by simplifying the left side of the equation:
10x - 2 - 6x = 4x - 2
Now, simplify the right side of the equation:
3x - 2 + x = 4x - 2
After simplifying both sides, we have:
4x - 2 = 4x - 2
At this point, we can see that both sides of the equation are the same. This implies that the equation is an identity, meaning that it is true for all values of x.
Therefore, the solution to the equation is all real numbers.
In summary, the given equation, 10x - 2 - 6x = 3x - 2 + x, simplifies to 4x - 2 = 4x - 2, which is an identity and true for all values of x.