28.09 g of silicon contains 6.02 1023 silicon atoms. What is the mass in grams of 1.06 1025 silicon atoms?
See your post above.
To find the mass in grams of 1.06 x 10^25 silicon atoms, you can use the given information of the mass of 28.09 g of silicon containing 6.02 x 10^23 silicon atoms.
First, calculate the molar mass of silicon by dividing the mass of 28.09 g by the number of silicon atoms present in that mass (6.02 x 10^23 atoms):
Molar Mass of Silicon = Mass of Silicon / Number of Silicon atoms
Molar Mass of Silicon = 28.09 g / 6.02 x 10^23 atoms
Now, we can calculate the mass of 1 mole of silicon atoms:
Mass of 1 mole of Silicon = Molar Mass of Silicon x Avogadro's Number
Mass of 1 mole of Silicon ≈ (28.09 g / 6.02 x 10^23 atoms) x (6.02 x 10^23 atoms / mole)
Mass of 1 mole of Silicon ≈ 28.09 g/mol
Finally, we can use the calculated molar mass to find the mass of 1.06 x 10^25 silicon atoms:
Mass of 1.06 x 10^25 silicon atoms = (Mass of 1 mole of Silicon / 1 mole) x (1.06 x 10^25 atoms)
Mass of 1.06 x 10^25 silicon atoms ≈ (28.09 g/mol) x (1.06 x 10^25 atoms / 6.02 x 10^23 atoms)
Mass of 1.06 x 10^25 silicon atoms ≈ 1.87 x 10^2 g
Therefore, the mass in grams of 1.06 x 10^25 silicon atoms is approximately 1.87 x 10^2 grams.