Solve the Mathod of substitution
1/6(2x+3y)+x/3=8,1/2(7y-3x)-y=11
1/6(2x+3y)+x/3=8
1/2(7y-3x)-y=11
Rearranging things a bit to get rid of the bothersome fractions, we have
4x+3y = 48
-3x+5y = 22
Since y = (48-4x)/3,
-3x+5(48-4x)/3 = 22
Or,
-9x+240-20x = 66
29x = 174
x = 6
Now you can easily find y.