# physics

A 755 N diver drops from a board 10.0m above the water's surface.Find the diver's speed 5.00 m above the water's surface. Then find the diver's speedjust before striking the water.

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1. F=ma

where a=9.81m/s^2 (gravity)

solve for m

now use the formula:

(1/2)m*v^2 + m*g*h = m*g*h2+(1/2)*m*v2^2

m=755
v=0
h=10 (starting height)
h2=0 (final height)
v2 = ?? this is what we're trying to find.

try to solve for v2 given the equation.

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posted by Don
2. V^2 = Vo^2 + 2g*h = 0 + 19.6*(10-5) = 98
V = 9.90 m/s @ 5 m above the surface.

V^2 = 0 + 19.6*10) = 196
V = 14 m. Just before striking the surface.

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posted by Henry

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