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How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7gFe? Fe2O3(s) + 3CO(g) => 3CO2(g) + 2Fe(s)
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Study the balanced equation. 3Mg + Fe2O3 → 3MgO + 2Fe What is the theoretical yield for MgO when 0.52 mol of Mg and 0.28 mol of Fe2O3 react? 2.10 x 101 mol MgO 1.03 x 101 mol MgO 2.10 x 101 g MgO 3.39 x 101 g MgO
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d) 2Al(s) + Fe2O3(s) 2Fe(l) + Al2O3(s) Oxidation 2Al(s) 2Al+ + 2e- Reduction Fe23+ + 3e- 2Fe(l) Oxidation numbers for chlorine HCl = -1 MnO2(s)= +4 KMnO4(s)= +7 Oxidation numbers for manganese Mn(s)= ? MnCl2(s)= +7
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What is the entropy change associated with the chemical reaction that occurs when iron oxide is converted to its metal form? Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) A. Zero B. Positive C. Negative D. Cannot be determined I think
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Please explain the answer. Which statement about this reaction is correct? 2Fe(s)+3CO2(g)--->Fe2O3(s)+3CO(g) delta H = 26.6 kJ A. 26.6 kJ of energy are released for every mole of Fe reacted B. 26.6 kJ of energy are absorbed for
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2Fe+3H2O→Fe2O3+3H2 If 1.24 mol of water react, how many g of iron(III) oxide would be produced? I know that the answer to this is 66.0 g but I don't understand how to solve it.
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Which element is oxidized in this reaction? Fe2O3+ 3CO-(arrow)2Fe+3CO2
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How many moles of carbon monoxide are needed to react completely with 1.75 moles of iron oxide? based on this equation: Fe2O3(s)+3CO(g)--->2Fe(s)+3CO2(g)
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Equation: Fe2O3 + 2Al ---> 2Fe + Al2O3. How many grams of Fe2O3 react with excess Al to make 475g Fe? Can you show me step by step how to do it? My book says the answer is 679g Fe2O3.
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How do you balance these chemical equation? o Fe2O3 + 3H2 → 2Fe + 3H2O o 4NH3 + 5O2 → 4NO + 6H2O
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When 84.8 g of iron(III) oxide reacts with an excess of carbon monoxide, iron is produced. Fe2O3(s) + 3CO(g) ==> 2Fe(s) + 3CO2(g) what is the theoretical yield of iron?
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