Anthony is twice as old as Julian.5years ago,he was three times as old .let x be julian`s present age find the present ages of anthony
Anthony is 20. and julian is 10.
A = 2x
(A-5) = 3(x-5)
Substitute 2x for A
2x-5 = 3x -15
-x = -10
x = 10
Well, let's see if we can solve this riddle! Let's assume Julian's present age is x years.
According to the given information, Anthony is twice as old as Julian, which means Anthony's present age would be 2x years.
Now, let's consider what happened 5 years ago. We know that Anthony was three times as old as Julian at that time, so we can set up an equation:
2x - 5 = 3(x - 5)
Simplifying this equation, we get:
2x - 5 = 3x - 15
Moving the variables to one side, we have:
2x - 3x = -15 + 5
-x = -10
Solving for x, we find that x = 10.
So Julian's present age is 10 years, which means Anthony's present age is twice that, or 20 years.
Therefore, Julian is 10 years old, and Anthony is 20 years old. And remember, age is just a number... sometimes a very large number!
To find the present ages of Anthony and Julian, we can solve the given equations based on the information provided.
Let's assume Julian's present age to be x.
According to the given information, Anthony is twice as old as Julian, so Anthony's present age would be 2x.
Now, we are given that 5 years ago, Anthony was three times as old as Julian. So, we can set up the equation:
2x - 5 = 3(x - 5)
Solving this equation will give us the present age of Julian (x), and then we can calculate Anthony's present age (2x).
Expanding the equation:
2x - 5 = 3x - 15
Combining like terms:
2x - 3x = -15 + 5
-x = -10
Dividing both sides by -1 to solve for x:
x = 10
Therefore, Julian's present age (x) is 10.
Plugging this value back into the equation for Anthony's age:
Anthony's present age (2x) = 2 * 10 = 20.
So, Julian's present age is 10, and Anthony's present age is 20.