The initial speed of a body is 3.01 m/s.
What is its speed after 3.89 s if it accelerates
uniformly at 3.63 m/s
2
?
Answer in units of m/s
To determine the final speed of the body after 3.89 seconds, we can use the equation of motion for uniformly accelerated motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
u = 3.01 m/s (initial speed)
a = 3.63 m/s^2 (acceleration)
t = 3.89 s (time)
Substituting the given values into the equation, we have:
v = 3.01 m/s + (3.63 m/s^2)(3.89 s)
Now we can calculate the final speed:
v = 3.01 m/s + (3.63 m/s^2)(3.89 s)
v = 3.01 m/s + 14.1167 m/s
v = 17.1267 m/s
Therefore, the speed of the body after 3.89 seconds, with a uniform acceleration of 3.63 m/s^2, is approximately 17.1 m/s.
Vo = 3.01 m/s.
t = 3.89 s.
a = 3.63 m/s^2.
V = Vo + a*t. Solve for V.