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the width of a rectangle is 4cm and the length is 8 cm if both the width and the length are increased by equal measures, the area of the rectangle is increased by 64 cm 2. find the length and width of the larger rectangle

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  1. (4+x)(8+x) = 4*8 + 64
    x^2+12x-64 = 0
    (x-4)(x+16) = 0

    x = 4
    So, the rectangle is
    8x12 with area 96 (32+64)

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  2. a rectangle of length 12cm and breadth 9cm has its length increase by 4cm what is the increase in its area

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