# Maths

110 members of a sports club play atleast one of the games, football, basketball and volleyball. If 20 play football and basketball only, 15 play football and volleyball only, 26 play basketball and volleyball only, x play all the three games, 2x each play only one game, how many play basketball altogether?

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2. 52

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4. Let the Sports Club be denoted by U,
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F = Football
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V = Volleyball
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n(U) = 110
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n(FnBnC') = 20
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n(FnVnB') = 15
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n(BnVnF') = 26
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n(FnBnV) = x
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n(FnB'nV') = n(F'nBnV') = (F'nB'nV) = 2x
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Note: B', F' and V' denote the complements of the various sets(clubs).
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n(U) = n(FuBuV) + n(FuBuV)'
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In this case, n(FuBuV)' is empty.
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110 = 2x + 20 + x + 15 + 2x + 26 + 2x
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110 = 61 + 7x
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49 = 7x
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x = 7
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n(B) = 20 + 26 + x + 2x
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n(B) = 20 + 26 + 3x
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n(B) = 20 + 26 + 21
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n(B) = 67
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~Darematics(07034495462)

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5. 67 members play basketball altogether

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6. Pls how was the answer 52 gotten

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7. Pls Ayodeji And Edidiong Umanah How Did U Get 52 To Be The Answer

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8. How many played football and how many played volleyball. Please I need a straight answer

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9. Pls how was 52 gotten

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10. pls how did you get 52

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11. Thank you so much
Have been trying it all day but still didn't get

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